What is the answer?

[Kaitou Kid Legendary Thief]

Nope. Try and draw it. It'll become easier that way.

Lol I'm on the streets now dun think I can draw anything lols... Guess I have to use my head for now

[Noir]

That's hard. I got the answer because I did something. I don't want to spoil the fun though, just because I Google'd it. *ebil laf* No, really, I tried, but I think my brain isn't enough for it. T.T

[phantomlady1101]

9

*fishes out mathcounts problems* This is one of my favorites...

Fido’s leash is tied to a stake at the center of his yard, which is

in the shape of a regular hexagon. His leash is exactly

long enough to reach the midpoint of each side of

his yard. If the fraction of the area of Fido’s yard that

he is able to reach while on his leash is expressed in

simplest radical form as ((√ a )/ b )π, what is the value

of the product ab?

Now this is a real math problem. There's no point in extremely long ones that you just feed to a calculator.

Edit: The extra space in the parenthesis is because it made the b and the ) into a smilie..

Oi, oi, I'm in grade 6!!!

[Kaitou Kid Legendary Thief]

]grade 6 can solve it too also i think.

You just have to search for the formula online for hexagon and circle.

However, it seems my math was wrong >_<

hmm... lemme guess

answer = 12a√a

or = 12a^3/2

???

[phantomlady1101]

]grade 6 can solve it too also i think.

You just have to search for the formula online for hexagon and circle.

However, it seems my math was wrong >_<

hmm... lemme guess

answer = 12a√a

or = 12a^3/2

???

I mean my English isn't enough to understand the problem!!!!

[Kaitou Kid Legendary Thief]

Oooooo

[Aeyra]

]grade 6 can solve it too also i think.

You just have to search for the formula online for hexagon and circle.

However, it seems my math was wrong >_<

hmm... lemme guess

answer = 12a√a

or = 12a^3/2

???

I asked what the product of ab is...

[Kaitou Kid Legendary Thief]

9

*fishes out mathcounts problems* This is one of my favorites...

Fido’s leash is tied to a stake at the center of his yard, which is

in the shape of a regular hexagon. His leash is exactly

long enough to reach the midpoint of each side of

his yard. If the fraction of the area of Fido’s yard that

he is able to reach while on his leash is expressed in

simplest radical form as ((√ a )/ b )π, what is the value

of the product ab?

Now this is a real math problem. There's no point in extremely long ones that you just feed to a calculator.

Edit: The extra space in the parenthesis is because it made the b and the ) into a smilie..

So the area of the circle = πr²

area of hexagon = ((3√3)/2) r²

ratio = 2 /9(√3)π

so a= 3 and b = 9/2

so I suppose ab = 27/2 = 13 1/2?

[Aeyra]

It's a whole number.

[conanshinichi]

Number?

1+2(23-1)x12-12x0-12+12-1-1+4-2+12÷2=?

[Wildheart888]

13/12

That's so mean of you to make me answer that.

1/36 + 1/7 + 1/3 + 2/7 = ? *ebil laf*

No one answered this yet, right? >_<

198/252?

56!

3+5x5=?

And isn't it 55?

[Cindy-Chen]

11/14?

17!-5!

[A L]

Prove that if two sides of a triangle are equal then the corresponding angles are also equal. Very simple.

From: My textbook. Theorum#2/30

[mystery fanatic]

Prove that if two sides of a triangle are equal then the corresponding angles are also equal. Very simple.

There are many Postulates and Theorems regarding triangle congruence. Two of those are Side-side-side (SSS) congruence and Side-included angle- side (SAS) congruence. I'm assuming you meant the latter since if it was the former you would've stated three sided.

Moving on, when 2 sides and the included angles (angle that consists of the two sides) of the triangles are congruent, then the triangles are also congruent. And according to the CPCTC or Corresponding Parts of Congruent Triangles are Congruent, the corresponding angles are also equal.

*I will not post a question until my answer is deemed correct since there seems to be complications with this game.

[Moon Kid]

91{9+5}=

[Kaito Natake]

14 o3o

 

3(3.14)r squared equals? XD

[Shreevatsa]

1000

 

 e= ???/