AJ M. Posted September 2, 2011 Report Posted September 2, 2011 ABCD= 2368 take away the + sign? same amount of 1's and 2's #1 is correct! The other two, wrong. 1) above 2) flip it over 3) number of ones add up to 4 two's also add up to 4 #2 is correct, but #3 is wrong. Hint for #3: It's like no other equation when it comes to this.
Kaitou Kid Legendary Thief Posted September 2, 2011 Report Posted September 2, 2011 Erm there's only one way to arrange the numbers?
AJ M. Posted September 2, 2011 Report Posted September 2, 2011 Erm there's only one way to arrange the numbers? You can arrange them like 1+12=2+11 or 12+1=2+11 and other ways so nope. Another hint: Rearranging
Moonlight Magician Posted September 2, 2011 Report Posted September 2, 2011 tsk....brain dead. Does it form a word or something?
AJ M. Posted September 2, 2011 Report Posted September 2, 2011 tsk....brain dead. Does it form a word or something? Nope... Hint: But as words, there is something.
Kaitou Kid Legendary Thief Posted September 2, 2011 Report Posted September 2, 2011 11+2=12+1 Eleven+Two=Twelve+One *thinks* I dont understand DX
AJ M. Posted September 2, 2011 Report Posted September 2, 2011 11+2=12+1 Eleven+Two=Twelve+One *thinks* I dont understand DX You are on the right track with that equation with the words. Now just think deeper
Kaitou Kid Legendary Thief Posted September 2, 2011 Report Posted September 2, 2011 You are on the right track with that equation with the words. Now just think deeper I GET IT!. :rolleyes: :rolleyes:
AJ M. Posted September 2, 2011 Report Posted September 2, 2011 I GET IT!. :rolleyes: :rolleyes: Nice! Let's see if someone else gets it
Lia. Posted September 2, 2011 Report Posted September 2, 2011 If you solve it out, it becomes: 13 = 13?
AJ M. Posted September 2, 2011 Report Posted September 2, 2011 If you solve it out, it becomes: 13 = 13? If that was the case, I couldve put 137-124=3+10. Try looking at the hints above.
Kim-Chan Posted September 3, 2011 Report Posted September 3, 2011 I think I get it ... 11+2=12+1 ---> Eleven+Two=Twelve+One If you re-arrange the letters.. Twelve+One also spell out Eleven+Two and vice-versa
AJ M. Posted September 3, 2011 Report Posted September 3, 2011 I think I get it ... 11+2=12+1 ---> Eleven+Two=Twelve+One If you re-arrange the letters.. Twelve+One also spell out Eleven+Two and vice-versa Nice job!
Kim-Chan Posted September 3, 2011 Report Posted September 3, 2011 Nice job! Thanks, but it's only because you gave out some hints, otherwise, I probably couldn't solve riddles for my life, but I like em' cause' they're challenging.. I have some more riddles, probably won't be very long until you guys figure em' out though.. 1.) 'What belongs to you, but is used more often by your friends?' 2.)'I am taken from a mine and shut up in a wooden case from which I am never released and yet I am used by almost everybody. What am I?' 3.)'If a fire hydrant has H2O inside what does it have on the outside?' 4.)'A doctor and a bus driver are both in love with the same woman an attractive girl named Sarah. The bus driver had to go on a long bustrip that would last a week. Before he left he gave Sarah seven apples. Why?'
Rukia Kurosaki Posted September 3, 2011 Report Posted September 3, 2011 1) Your name. 2)Lead. (For Pencils) 3)K9P. (Canine p**) 4)To keep the doctor away while he was gone. (An apple a day...)
Kim-Chan Posted September 3, 2011 Report Posted September 3, 2011 1) Your name. 2)Lead. (For Pencils) 3)K9P. (Canine p**) 4)To keep the doctor away while he was gone. (An apple a day...) Great job~! Got ALL of them right! *sigh* I'm just not good at giving riddles Anyone else want to give it a shot~?
aika Posted November 9, 2011 Report Posted November 9, 2011 well I'll post next riddle it's pretty hard if you don't think The four people in this puzzle all competed in different classes of dog agility at a recent competition. The competitions all required the dogs to run over jumps, through tunnels and various other obstacles in as quicker time as possible. Each had a different result - one came first, one third, one fourth and one ninth. All four dogs were each of a different breed. Can you work out who handled which dog, at what level each competed, the place each finished in and the breed of each dog? 1. If Tiff finished first then Terry finished fourth. 2. If Terry finished fourth then Jago is a collie otherwise Jago is not a collie. 3. If Jane competed in the Senior class then she finished third. 4. If Jane competed in Novice then she finished fourth. 5. The dog that finished ninth was an alsatian. This was either Jago, in which case Jago competed in the Elementary class, or this was Kelly, in which case Terry handled Kelly. 6. Mark won Starters. 7. If Mark's dog is called Patti then Patti is a labrador otherwise Patti is a collie. 8. Ruth's dog is called Jago. 9. If Jago finished fourth then she competed in the Novice class otherwise she competed in the Senior class. 10. If Patti finished first then Terry's dog is an alsatian otherwise Terry's dog is a collie. 11. If Jane's dog is a doberman then Jane finished fourth otherwise Jane finished third. Handler's Names: Jane, Mark, Ruth and Terry Dog's Names: Tiff, Patti, Jago and Kelly Breed: Alsatian, Collie, Labrador and Doberman Level: Starters, Elementary, Novice or Senior Answer should be like this Dogs Handler's class place breeds 1 -------- ----- ----- ------ IN place of"---" fill them up four of them.
kfnnapa Posted November 10, 2011 Report Posted November 10, 2011 Alright let's see if I understood your rules and how to post it. 1st) Mark/Patti/Labrador/Starter 3rd) Jane/Tiff/Collie/Senior 4th) Ruth/Jago/Doberman/Novice 9th) Terry/Kelly/Alsatian/Elementary
aika Posted November 10, 2011 Report Posted November 10, 2011 Alright let's see if I understood your rules and how to post it. 1st) Mark/Patti/Labrador/Starter 3rd) Jane/Tiff/Collie/Senior 4th) Ruth/Jago/Doberman/Novice 9th) Terry/Kelly/Alsatian/Elementary correct time for next riddle A woman had three old coins - a silver dollar, a quarter, and a dime. Each coin was a little battered and had a piece missing. She found that exactly the same fraction had broken away from each coin. What fraction of each was missing if the value of the remaining bits of coins was now exactly one dollar in total? For this puzzle it can be assumed that ½ of a coin is worth ½ of its value. Hint:-A dollar is 100 cents, a quarter is 25 cents and a dime is 10 cents.
Kaitou Kid Legendary Thief Posted November 10, 2011 Report Posted November 10, 2011 Oooh is this math? --------------------------------- Let a be the fraction broken off. 100 x a + 25 x a + 10 x a = 100 so a (100 + 25 + 10) = 100 a = 100/ (135) a = 20/27 Is this the answer? ---------------- Edits: I just realised the question was... "What is left is one dollar" instead of what's broken off... D: -------- Okay rewrite answer -------- Let a be the fraction left. :V So, the fraction broken off = 1 - a = 7/27 ------------------------------------
aika Posted November 10, 2011 Report Posted November 10, 2011 Oooh is this math? --------------------------------- Let a be the fraction broken off. 100 x a + 25 x a + 10 x a = 100 so a (100 + 25 + 10) = 100 a = 100/ (135) a = 20/27 Is this the answer? ---------------- Edits: I just realised the question was... "What is left is one dollar" instead of what's broken off... D: -------- Okay rewrite answer -------- Let a be the fraction left. :V So, the fraction broken off = 1 - a = 7/27 ------------------------------------ awesomely done 2'nd one is Correct Time for next riddle What value of * makes the following correct */* - */2 + */4 =*/12 IN here "/" doesn't necessarily mean divide Hint :- The answer is a whole number less than 10.
Kaitou Kid Legendary Thief Posted December 7, 2011 Report Posted December 7, 2011 12 - 12a/2 + 12a/4 = a 12 - 6a + 3a = a 12 = 6a - 3a +a 12=4a a = 3 *= 3? This looks like an equation, so erm pardon me if I'm wrong...
Valkyrie Posted December 18, 2011 Report Posted December 18, 2011 12 - 12a/2 + 12a/4 = a 12 - 6a + 3a = a 12 = 6a - 3a +a 12=4a a = 3 *= 3? This looks like an equation, so erm pardon me if I'm wrong... That's what I thought as well. But then aika said that it the slashs don't mean divide so I have no idea if this is right.
Cindy-Chen Posted December 19, 2011 Report Posted December 19, 2011 Looks hard. O.o I don't know. :embarassed:
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