Thats correct!
Solution:
when there are only two thieves left-
thief 1 and thief 2. Thief 2 will suggest 100 0.
Thief 1 will not want this outcome, so as long as thief 3 gives him anything at all he will accept.
Thief 3 will suggest 99 0 1. Thief 1 and 3 accepts. So there will be more than 50% agree. Thief 2 will not want this outcome, so he will allow thief 4 to succeed if he was given anything at all.
Thief 4 will suggest 99 0 1 0. Thief 1 and 3 will receive nothing. They will not let thief 4 decide on the plan, so they will support thief 5 if he gave them anything at all.
Thief 5 will need two people on his side. Since he needs 3 people to agree including himself. So he needs 2 others. He will then cooperate with thief 1 and 3 since he knows thief 4 will give them nothing, and so they will gladly accept any amount that he is going to offer. In this case, thief 2 and 4 will not receive anything
Thief 5: 98 0 1 0 1
Thus, thief 6: 98 0 1 0 1 0
thief 7: 97 0 1 0 1 0 1
thief 8: 97 0 1 0 1 0 1 0
thief 9: 96 0 1 0 1 0 1 0 1
thief10: 96 0 1 0 1 0 1 0 1 0.
Got it?? Wanna digest the information again?