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How does one calculate the probability of getting a straight in the same suit with a 8 card hand with a deck of cards of three suits and no face cards (but including 10)?
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First, there are three suits. Secondly, consider first, that there are 18 ways to get the five cards needed for a straight. However, there are still 3 cards unaccounted for. There are 2300 different combinations of three cards. Each combination combined with an straight makes a distinct hand. So, 41400.
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I don't have the answer ...
Its a school question... D:
btw the straight is a five card straight out of 8 cards... >__<
E.g 12345 789 with 12345 of the same suit.
How do we do the calculation with it?
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Oh wait, I missed the whole 2300 3-card combinations left thing....XD" nevermind my attempt again.
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