Forever Lost Posted May 5, 2011 Report Posted May 5, 2011 I'm having trouble figuring this out right off hand, so I figured I'd see if anyone could explain it, or give some insight that I could use on making a two-column proof for this. Here's the info:
Misaki-chan Posted May 5, 2011 Report Posted May 5, 2011 O.o What the...? Too... hard... brain.... overload..... *explodes* Sorry I'm no help. ^.^; You should ask Aeyra or Cure-kun. They're smart in math.
Aeyra Posted May 5, 2011 Report Posted May 5, 2011 Use parallel lines and vertical angles and the answer should come right out. Sorry, in a rush. Longer explanation layer.
Detective Rohit Posted May 5, 2011 Report Posted May 5, 2011 Quite easy: I dont know how you proove, but here is the proof Before that take the point of intersection of the line CG and EA as.. Say point M In ABDE is a //gram, CD is // to EM and DF is // to CG In CDFG is a //gram, CD is // to FG and DE is // to BA Therefore, EM is // to FG and CM is // to BA (The Trick and it means that FGCM is a //gram too) Now Angle G = Angle M (FG is // to EM) Now Angle M = Angle A (CM is // to BA) Hence Angle G = Angle A.
Kaitou Kid Legendary Thief Posted May 5, 2011 Report Posted May 5, 2011 Eh... what do you mean by two column proof? Well if you just want explanations, i can give a fairly detailed one: First part Given: ABDE and CDFG are parallelograms --> BD//AE (BD parallel to AE *from diagram*) and CD//FG Since C lies on line BD, BD//CD From the two statements above, we know that BD//AE//CD//GF --(1) Second part Given: ABDE and CDFG are parallelograms --> DF//CG and BA//DE from diagram Since E lies on DF, DE//DF From these two statements above, we know that DE//DF//CG//BA --(2) We need to prove: angle G is the same as angle A, which means this - PROVE angle CGF = angle BAE from equation (2), we know that CG//BA from equation (1), we know that GF//AE Thus, using rule of corresponding angles CGF ~= BAE
tengaku squared Posted May 6, 2011 Report Posted May 6, 2011 If ABDE and CDFG are parallelograms, you could do it like this: 1) ABDE and CDFG are parallelograms. (given) 2) Angle A is congruent to Angle D. (opposite angels of a parallelogram are congruent) 3) Angel D is congruent to Angle G. (same as 2) 4) Angel A is congruent to Angle G. (If two angles are congruent to the same angle, they are congruent)
Aeyra Posted May 6, 2011 Report Posted May 6, 2011 *meh* YOU GUYS STOLE MY EXPLANATION!!!! Sorry... I'm having a hard time getting onto DCW other than school hours and five minutes in the morning... Therefore I can't post very long things.
Forever Lost Posted May 6, 2011 Author Report Posted May 6, 2011 Thanks, ya'll, that was really helpful.
Balthazar Manfredie Posted May 17, 2011 Report Posted May 17, 2011 i never did like geometry, but had to learn it
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now