Kaitou Kid Legendary Thief

I dont understand lol So it must be more difficult to understand

Okay goodnight!

That's a difficult way to understand XD

so basically, you have to write down all factors of the coefficients of p.

Then you write down all coefficients of the constant.

then find a pair of factors which can pair up with each other to give the middle number.

and thats it. \o/

(2k+3)(2k-3)???

This is answer for?

21p(2) + 15p - 6

(__p + ___) (__p + ___)

(21p + ___) (1p + ___)

(Note: 21 - 6 = 15)

So...

(21P - 6)(1p + 1)

Then...

30p(2) - 19p - 4

(__p + ___)(__p + ___)

factors of 30: 30X1, 15X2, 3X10, 5X6

factors of 4: 4X1, 2X2

to get -19, we need 5X6 and 4X1

(Note: 5-24)

So

(5p-4)(6p+1)

Actually I teach you a method

lets say: Like the previous question:

6K(2) + K - 15

You write this down:

6K(2) - 15

.

(__K + __)(__K - ___)

Then you fill in the blanks.

for the ones infront of K, they must multiply to get 6.

(2k-3)(3k+5) <-------

(2k-3)(3k+7) <-------

I think~

Yay! \o/ These are quite simple. The numbers are still small~ XD

sorry change the r to t

(8-r)(3+r) <------

(9-r)(6+r) <------

But do you know how to get them? Its pretty easy you know... These can be calculated in the brain.

LOL I just realised I posted on my own wall

so you need to factorise it? Or get the answer?

2(r-8)(r-3) <-----

2(r-5)(r-2) <-----

Need me to explain?

so you need to factorise it? Or get the answer?

2(r-8)(r-3) <-----

2(r-5)(r-2) <-----

Need me to explain?

trinomial? Ah~ Should be able to Care to share?

I see XD Need my help?

(Actually not sure whether she can help but she's pretty interested when it comes to math so... )