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Detective Conan World

Anti-APTX4869

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Posts posted by Anti-APTX4869


  1. I watched it since they first aired in Korea, which I think it was around mid-January 2000.
    I've known about it when I read the manga before... but I don't remember when I first read it. I'm sure I was reading it as a kid as soon as I learned how to read Korean so that's around 1996+...
     

    roughly I've been a fan of Conan since I was a little kid... 18 years at most, 15 years at least.


  2. I don't mind whatever people call me really. You don't have to have honorifics, but you are welcome to do so if that's comfortable.

     

    One thing I really hate is word problems. I never really liked them since I was 3rd grade because of the language barrier despite how much I love math,

    Truthfully, I don't know. I'm just gonna guess with 126 using combination. 9! / [5!(9-5)!] = 9x2x7 = 126. but that seems really odd. 

     

    ...oh about giving question... I kinda don't want to. I might give something too confusing....

    so let's go with an easy one:

     

    I'm thinking about a 3 digit number that can be divided by 11.

    If I took that number and added each digits to find that the sum is 21, what must be one of its digit?

     

    (... if there's more than one answer than I'm screwed lol...)


  3. Ah crap, 4th time ever. But someone has to freaking confirm, right?

    First of all: o_O how did infinite sums get here?

    Second of all: It's actually quite simple. Sorry for typos. I'm on a tablet.

    1/n(n+1)(n+2) = 1/2(1/(n)(n+1)- 1/(n+1)(n+2))

    Proof: common denominator- n(n+1)(n+2)

    So, the first fraction would have a numerator of n+2, and the second one, n. Their diffrerence is 2, and multiplying that by 1/2 would result in 1 over the denominator.

    =1/2(1/1x2 - 1/2x3 + 1/2x3 - 1/3x4 + ... + 1/98x99 -1/99x100)

    =1/2(1/1x2 - 1/99x100) (all the other terms would be cancelled)

    =1/2(1/2 - 1/9900)

    =1/2(4949/9900)

    =4949/19800

    I noticed my typo in almost every step. it's not sum from n=2 to 100 but n=2 to 99....

    Your way makes things much easier... it's basically comes down to the same thing though since the equation from my solution will equal to yours if I did it correctly.

    1/4 + (-1)/(2x(x+1))

    1/4 - (1/(2x(x+1)))

    1/2 (1/2 - 1/ x(x-1)) ----- x = 99 (not 100, which I made a huge mistake in my solution.)

    1/2 (1/2 - 1/ 99(100))

    1/2( 1/2 - 1/9900) yay we get the same answer!

    But then again, I like things complicated for some reason because... uhh... idk

    i just like thinking through long steps. I just find them more entertaining. I do wish I can think of such methods quickly though.

    I love how math can be manipulated, having multiple ways to solve a problem... or sometimes none, which is such a depressing moment. =_=

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